On 01/25/2013 10:37 PM, Peter Alexander wrote:
Would this be possible without breaking the grammar?bool isPalindrome = getRange().(r => equal(r, retro(r)));
Yes.
I find this way of writing that expression more natural and efficient than the alternatives: auto r = getRange(); bool isPalindrome = equal(r, retro(r)); or bool isPalindrome = (r => equal(r, retro(r)))(getRange());
bool isPalindrome = getRange().ap!(r => equal(r, retro(r))); where auto ap(alias a,T...)(T b)=>a(b);
