On Monday, 22 April 2013 at 09:03:24 UTC, Peter Alexander wrote:
mixin template A() {
extern(C) int foo() { return 1; }
}
mixin template B() {
extern(C) int foo() { return 2; }
}
mixin A a;
mixin B b;
void main() {
int x = a.foo() + b.foo();
}
If both foo's have the same symbol, then how am I able to
disambiguate them in code?
Maybe duplicate extern(C) template mixin symbols need to be an
error?
If there are true duplicates then it would need to be an error.
However, if a mixin uses a mixin identifier then it's going to
need to be mangled anyway, so only
mixin A;
mixin B;
would have to be an error. It already is an error, but
unfortunately only when you reference the content of the mixin,
not at the mixin statement.
