On Sunday, 17 November 2013 at 05:30:24 UTC, Jean Christophe
wrote:
You mean, sort!`a.foo < b.foo` ?
Yes.
An indirect sorting, assuming a and b to be ojects of class
SomePotentialyLargeClass.
Because the array to sort contains pointers only, all the data
movement is essentially the same as if we were sorting integer.
If the range elements are reference types, that's what will
happen (unless they overload opAssign oslt). Otherwise, there's
makeIndex (already mentioned by Andrei), or you could also do it
by hand:
1. r.length.iota.array.sort!((a, b) => r[a]<r[b]);
2. r.length.iota.map!(a => &r[a]).array.sort!((a, b) => *a<*b);
r.map!`&a` doesn't work though, because we don't get a reference
to the range element in the predicate.
