Re: std.algorithm missing for_each?

[Idan Arye]

On Wednesday, 5 February 2014 at 11:21:12 UTC, bearophile wrote:
myRange
.each {
   e.someOperation;
};

Possibly better:

myRange
.each (e) {
    e.someOperation;
};


Bye,
bearophile

I is unclear from the syntax whether `(e)` is a the argument list 
and `{...}` is a block lambda or the property syntax is used and 
`(e) {...}` is a regular lambda.

How about using the Ruby style of blocks:

    myRange
    .each do(e) {
        e.someOperation;
    };

This will also give a nice syntax when passing named functions:

    myRange.each do writeln;



Alternatively, we can fuse the delegate definition with the 
higher order function's call syntax like this:

    myRange
    .each (auto e) {
        e.someOperation;
    };

Here, `(auto e)` *is* the argument list of `each`, but it's clear 
that `e` is not an argument passed to `each` because it uses the 
declaration syntax rather than being an expression. Actual 
arguments could be passed in the same list:

    forEachInRange(auto i, 0, 10) {
        ...
    }

This, ofcourse, will require some special syntax for declaring 
the higher order function.