On 2014-03-24 04:37:22 +0000, Michel Fortin <[email protected]> said:

But try this instead, the result is even shorter:

Oops, messed up my patterns. Here's a hopefully fixed front():

dchar front(char[] s)
{
 if (s[0] < 0b1000000)
   return s[0]; // ASCII

 // pattern     indicator  tailLength
 // 0b1100xxxx  0b00 (0)   1
 // 0b1101xxxx  0b01 (1)   1 == indicator
 // 0b1110xxxx  0b10 (2)   2 == indicator
 // 0b1111xxxx  0b11 (3)   3 == indicator
 // note: undefined result for illegal 0b11111xxx case

 auto indicator = (s[0] >> 4) & 0b11;
 auto tailLength = indicator ? indicator : 1;

 dchar result = s[0] & (0b00111111 >> tailLength);
 foreach (i; 0..tailLength)
     result = (result << 6) | (s[1+i] & 0b00111111);
 return result;
}

--
Michel Fortin
[email protected]
http://michelf.ca

Reply via email to