On Tue, 15 Apr 2014 13:46:11 -0400, bearophile <[email protected]>
wrote:
Steven Schveighoffer:
On the left hand side, the [] operator is special *for arrays* in that
it denotes you want to do an element-wise copy. On the right hand side,
this is not the case, [] is simply an operator. It's a no-op if the rhs
is an array, since [] just gets the array again.
Requiring it simply adds unneeded hoops through which you must jump,
What do you think are the reasons I suggested the enhancement for?
To make people write code the way you like? :)
Honestly, it's like you require someone to call a function like:
T foo(T)(T t){return t;}
Just so you can see the foo there. I understand the idea, but the result
is not logical, just superficial.
-Steve
