On Friday, 16 May 2014 at 23:14:13 UTC, Idan Arye wrote:
Another problem is that we now have to have an argument if we want to pass a template parameter, which is a serious limitation.
I'd say, it's not different from selection from an overload set. On Saturday, 17 May 2014 at 01:28:50 UTC, Idan Arye wrote:
When I see such a signature as `void myTemplateFunction( InputRange!int r ) {` I'm automatically assuming I can do things like `void function(InputRange!int) foo = &myTemplateFunction;`, but in our case I can't since it's a template.
One of possible applications of this feature would be specification of constraints for variable types to improve readability:
range!int r = ... So it should work like a normal type.
