Lars T. Kyllingstad wrote:
Daniel Keep wrote:
Lars T. Kyllingstad wrote:
Don wrote:
The operator which is REALLY missing is exponentiation.
I've been really missing that one.
Which operators could be used for exponentiation? I've only ever seen
a**b and a^b used, but I think those are out of the question for D.
-Lars
How about *^
^ isn't valid as a unary operator, thus a*^b cannot be mistaken for
a*(^b)
It's a bit of a cop-out combining the two, but should be unambiguous.
Yeah, not too bad. Would a^^b work?
-Lars
Yes. I think it's the best option.
Note that we already have the table:
bitwise logical
& &&
| ||
^ !=
so there's nothing else you'd want to use ^^ for.
People would get used to it pretty quickly. I think it looks better than
Fortran's **, actually. double y = x^^2;
