Ary Borenszweig Wrote: > In C# when you define a function that takes an out or ref parameter, > when invoking that function you must also specify ref or out. For example: > > void fun(ref uint x, double y); > > uint a = 1; > double b = 2; > fun(ref a, b); > > When I first started using C# it really annoyed me that I had to put > that keyword there just to get my program compiled. "I know what I'm > doing", I thought. But later, when reading the code, I found it very > helpful to know that my "a" could be changed when invoking "fun". As > always, code is read much more times than written, and I think this > little tips help better understand the code. > > What do you think?
IIRC, this is no more a case as of C# 3.0
