On Friday, 29 August 2014 at 17:29:49 UTC, deadalnix wrote:
Indeed, undefined behavior can be anything, by definition, and this cannot. Still, removing undefined behavior and replace it by undefined values cause the optimizer to have to prove that load/store won't fault, which is going to kill any expectation of performance.
I still don't understand what kind of fault your are talking about.
Granted if you store in more than one location you have to make at least one move, but if you only store in one location you have the same situation as if you are optimizing:
a=a; Clearly you can remove this without doing any loads or stores?
