Re: Mixin declarations not showing up in ModuleInfo

[Daniel Kozák via Digitalmars-d]

V Tue, 02 Dec 2014 04:05:16 +0000
bitwise via Digitalmars-d <digitalmars-d@puremagic.com> napsáno:

> On Monday, 1 December 2014 at 07:28:28 UTC, Daniel Kozák via 
> Digitalmars-d wrote:
> > V Mon, 01 Dec 2014 00:07:10 +0000
> > bitwise via Digitalmars-d <digitalmars-d@puremagic.com> napsáno:
> >
> >> > But I just try to say you can omit mixin word in template 
> >> > declaration. Because it doesn't have any effect.
> >> 
> >> mixin != mixin template != template
> > Yes and no :)
> >
> > import std.stdio;
> >
> > mixin template t1() {
> >     int x = 5;
> > }
> >
> > void main(string[] args)
> > {
> >     mixin t1;
> >     writeln(x);
> > }
> >
> > is same as:
> >
> > import std.stdio;
> >
> > template t1() {
> >     int x = 5;
> > }
> >
> > void main(string[] args)
> > {
> >     mixin t1;
> >     writeln(x);
> > }
> 
> Heh... Guess you got me there ;)
> 
> That is strange though... I don't see in the docs that mixin 
> templates have been deprecated, and can't seem to find anything 
> that doesn't work in both templates and mixin templates. The 
> "mixin name" usage is also not present in the docs for regular 
> templates.

There is one limitation of mixin template. You can not do this
(instantied mixin template):
import std.stdio;

mixin template t1() {
    int x = 5;
}

void main(string[] args)
{
    alias t1!() T;
    writeln(T.x);
}


But this is valid:

import std.stdio;

template t1() {
    int x = 5;
}

void main(string[] args)
{
    alias t1!() T;
    writeln(T.x);
}