On 12/10/2014 8:56 PM, deadalnix wrote:On Thursday, 11 December 2014 at 03:27:08 UTC, Walter Bright wrote:I disagree. It's critical for chaining one function to the next.I one can't return, one can't chain.I guess I'm not seeing the problem.
a.foo().bar() is the same as bar(foo(a)), that is, using the returned value as first parameter. If you can't return, you can't chain.
