On 12/29/14 10:36 AM, Julian Kranz wrote:
On Monday, 29 December 2014 at 15:25:13 UTC, Daniel Kozak wrote:
On Monday, 29 December 2014 at 15:17:30 UTC, Julian Kranz wrote:
Thank you for your answers. All of your suggestions go into the right
direction, however there's still one thing left that breakes it: the
method itself (blah()) needs to be marked as const to be callable on
a const object. Therefore, I need something like
void blah(...)(...) if(this ia const object) const : nothing {
}
Not in my solution, because blah is not a "method". T will become const
if the callee is const. As I said, you may have to do T : const(Hugo).
Did you try my solutions? It doesn`t need blah to be const
Uuuhm, you're right, it works :-D I don't completely understand why the
compiler does not require the function to be sonst any longer...
I think Daniel's solution would work if the compiler infers const. I'm
not sure that it does, but if it works, it does :)
The compiler can infer attributes if a function is a template. Not all
attributes, but some of them.
-Steve
