On 12/29/14 9:12 PM, Matt Soucy wrote:
On 12/29/2014 02:07 PM, anonymous wrote:
On Monday, 29 December 2014 at 13:20:39 UTC, Julian Kranz wrote:
Thank you for your answer. This kind of thing also works for C++, but that would mean 
that I would implement the whole visitor twice - one const and one non-const version. Is 
that really the only way? Can't I tell the D compiler that "the argument of that 
lambda shares the const-ness of the current object"?

D offers "inout"; this actually aims into the right directing, but I guess it 
does not help here.

Is there any "static if"-something construct to check the const-ness of an 
object?

There's a pattern I suggested before[1] that I'd like to mention
in addition to the template solutions Steven Schveighoffer and
Daniel Kozak gave:

Call the non-const overload from the const overload and cast
accordingly.

In your case:

    void blah(void function(Hugo h) f) {
      f(this);
    }
    void blah(void function(const Hugo h) f) const {
      (cast(Hugo) this).blah(cast(void function(Hugo)) f);
    }

This is safe as long as the non-const overload does not mutate
the object when f doesn't. BUT you have to make sure of that
yourself; the compiler can't help anymore.

[1]
http://stackoverflow.com/questions/22442031/how-to-make-a-template-function-const-if-the-template-is-true/22442425#22442425
Wait, is there a reason that you cast away const instead of adding it? I 
haven't done too much with D const lately, but in C++ I know that I would have 
the non-const version call the const version instead - seems a bit safer, and 
the compiler can check it a bit beter.


It would still require a cast. Remember the function pointer passed to non-const blah requires a non-const Hugo. So you would have to cast at least the function pointer to void function(const(Hugo)). This doesn't sit as well as casting the other way (you can always call a function that takes a const Hugo with a non-const Hugo), although practically speaking, there isn't any damage done. However, the call of f inside the const blah function would violate const. If f were marked as pure, this could be actually damaging.

Either solution looks ugly and error-prone to me. I like the template solution the best, either as a template this member or a UFCS template function call. The delegate solution I posted earlier is neat, but seems too inelegant.

-Steve

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