== operator

[Jonathan Marler via Digitalmars-d]

I've recently looked at how the '==' operator works with classes. 
 I was disappointed to find that 'a == b' always gets rewritten 
to:

.object.opEquals(a, b);
The reason for my disappointment is that this results in 
unnecessary overhead. I would think that the compiler would first 
try to rewrite the '==' operator using a type-specific opEquals 
method, then fall back on the generic version if one did not 
exist.  Is there a reason for this?