On Wednesday, 28 January 2015 at 13:48:45 UTC, Dicebot wrote:
Isn't that what your first proposed solution is about? That was
my understanding and I liked that understanding :) To be 100%
clear :
export void foo(T : int)(T x)
{
bar(x);
}
private void bar(int x) { }
I'd expect `bar` to be exported into resulting binary so that
it can be linked against by any users of `foo` but for any
attempt to call `bar` directly from D code to fail because of
protection violation. If someone wants to circumvent protection
by forging mangling - shooting own feet is allowed.
So you'd want bar to be duplicated on both sides ? This is gonna
cause problems with di files.
