On Thursday, 30 April 2015 at 03:58:44 UTC, Freddy wrote:
On Thursday, 30 April 2015 at 01:19:45 UTC, Vladimir Panteleev wrote:
Because "copy" is still modified every time "i" is.
But shouldn't copy be redeclared every loop iteration (or the compiler could pretend to redeclare it).

No, it will have the same address every time.

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