Aren't predictable branches cheap on current architectures?
Atila
On Tuesday, 19 May 2015 at 05:16:48 UTC, Andrei Alexandrescu
wrote:
So there's this classic trick:
bool isPowerOf2(uint x)
{
return (x & (x - 1)) == 0;
}
Pretty neat, but it wrongly returns true for x == 0. So the
obvious fix is:
bool isPowerOf2(uint x)
{
return x && (x & (x - 1)) == 0;
}
But that has branches in it. So I came up with:
bool isPowerOf2(uint x)
{
return (x & (x - 1) | !x) == 0;
}
which has no branches at least with dmd, see
http://goo.gl/TVkCwc.
Any ideas for faster code?
Thanks,
Andrei