Re: std.stdio.writeln should not accept infinite ranges?

[Andrei Alexandrescu via Digitalmars-d]

On 11/12/2015 08:18 PM, Xinok wrote:
The following code compiles and runs:
import std.stdio, std.random;

void main()
{
     writeln(rndGen);
}

Since rndGen is an infinite range, this code runs forever. It seems to
be that we need to add a check for isInfinite on writeln and other
related functions.

Does anybody have a use case where this is actually practical? I don't
see a reason for allowing infinite ranges here, considering how easy it
is to write "range.take(n)".

Piping a program that produces infinite output into less is practical. 
-- Andrei