Re: Signed integer overflow undefined behavior or not?

[John Colvin via Digitalmars-d]

On Friday, 13 November 2015 at 12:06:43 UTC, Matthias Bentrup 
wrote:
On Friday, 13 November 2015 at 09:33:51 UTC, John Colvin wrote:
unsigned: f(v) = v mod 2^n - 1
signed: f(v) = ((v + 2^(n-1)) mod (2^n - 1)) - 2^(n-1)

I guess you meant mod 2^n in both cases...

haha, yes, sorry.