On Monday, 7 December 2015 at 23:52:38 UTC, NX wrote:
On Sunday, 6 December 2015 at 02:00:30 UTC, Andrei Alexandrescu
wrote:
Yah, error is the way to go. -- Andrei
Can I ask a question?:
Why we don't have a way to get an exact overload of function?
Something like:
void foo(int i);
int foo(float f);
//...
int function(float) foop = &foo::(float);
`&foo` is a special "type" that will implicitly convert to both
`void function(int)` and `int function(float)`. No special syntax
is needed, just trigger the conversion.
