On 1/17/2016 6:16 PM, jmh530 wrote:
On Sunday, 17 January 2016 at 19:47:46 UTC, Walter Bright wrote:
and yes, M.X.fooa() will wind up referring to the same externally defined
symbol X::fooa() as N.X.fooa().
Just for clarification.
Suppose instead of file2 having fooa, it has foob, so there is no conflict
within X as to the names. Even in this case, I would have to call fooa and foob
with M.X.fooa() and N.X.foob(). I couldn't use X.fooa() and X.foob(). However,
suppose only file1 exists. Then, I could call fooa as X.fooa() or M.X.fooa().
Yes. Or, in the last case, even just fooa().
