On Sunday, 20 March 2016 at 14:11:11 UTC, Nick Treleaven wrote:
On Saturday, 19 March 2016 at 23:16:40 UTC, Xinok wrote:
I took a quick look through Phobos but didn't see anything
similar so I wrote this as a proof of concept and to elicit
discussion. This also works should the function throw rather
than return gracefully.
http://dpaste.dzfl.pl/23c665bdae9e
Nice! This is more flexible than Go's defer as you can have
more than one stack of them.
I don't quite get this:
defer((int i) => writeln(i), i);
If it was defer(() => writeln(i)), would that do the same?
(Dpaste won't seem to let me edit your example on my tablet).
No that's not the same, since the reference to i does not change
when doing:
defer(() => writeln(i))
However with defer((int i) => writeln(i), i) you pass the value
of i to the lambda expression which stores the value in a new
reference.
The problem with the first one is the value will always be the
last value of i.
