On 15.04.2016 23:03, Andrei Alexandrescu wrote:
On 04/15/2016 04:47 PM, Steven Schveighoffer wrote:
There's no difference between a function that declares its variables
inout within its parameters or one that declares them locally.
So now we get to things like:
void fun() {
inout int ohHello = 42;
...
}
How to explain such a construct? Not to mention globals of that type are
not allowed.
Andrei
It's an int that has not decided yet whether it wants to be mutable,
const or immutable and goes out of scope before it is able to make up
its mind.
