On 02.06.2016 23:23, Andrei Alexandrescu wrote:
On 6/2/16 5:19 PM, Timon Gehr wrote:
On 02.06.2016 23:16, Timon Gehr wrote:
On 02.06.2016 23:06, Andrei Alexandrescu wrote:
As the examples show, the examples would be entirely meaningless at
code
unit level.
So far, I needed to count the number of characters 'ö' inside some
string exactly zero times,
(Obviously this isn't even what the example would do. I predict I will
never need to count the number of code points 'ö' by calling some
function from std.algorithm directly.)
You may look for a specific dchar, and it'll work. How about
findAmong("...") with a bunch of ASCII and Unicode punctuation symbols?
-- Andrei
.̂ ̪.̂
(Copy-paste it somewhere else, I think it might not be rendered
correctly on the forum.)
The point is that if I do:
".̂ ̪.̂".normalize!NFC.byGrapheme.findAmong([Grapheme("."),Grapheme(",")])
no match is returned.
If I use your method with dchars, I will get spurious matches. I.e. the
suggested method to look for punctuation symbols is incorrect:
writeln(".̂ ̪.̂".findAmong(",.")); // ".̂ ̪.̂"
(Also, do you have an use case for this?)
