On Monday, 20 June 2016 at 13:50:45 UTC, Johan Engelen wrote:
On Monday, 20 June 2016 at 12:33:31 UTC, Guillaume Chatelet
wrote:
class Expression;
extern(C++) void foo(Expression);
Question:
---------
- How to I get the linkage for Expression from a
FunDeclaration? This will ensure the added indirection is put
only for the D classes, not the C++ ones. I tried looking at
Parameter, ClassDeclaration or TypeClass but couldn't find it.
A FuncDeclaration is a Declaration, which contains the field
`LINK linkage;`. That's the one you want.
-Johan
Thx Johan. I'm confused though: `FuncDeclaration.linkage` is the
linkage for the function (which I already know is C++ function
since I'm mangling it) but I need the linkage for the Parameter.
Parameter has a Type but I can't get the linkage from here. What
did I miss?
