void writeln(T...)(T args) {
if (__ctfe){
debug {
__ctfeWriteln(args);
}
} else {
// ... current implementation
}
}
That will not work. The signature is void __ctfeWriteln(const string s)
Stefan Koch via Digitalmars-d Sat, 03 Sep 2016 22:01:49 -0700
void writeln(T...)(T args) {
if (__ctfe){
debug {
__ctfeWriteln(args);
}
} else {
// ... current implementation
}
}
That will not work. The signature is void __ctfeWriteln(const string s)