void writeln(T...)(T args) { if (__ctfe){ debug { __ctfeWriteln(args); } } else { // ... current implementation } }
That will not work. The signature is void __ctfeWriteln(const string s)
Stefan Koch via Digitalmars-d Sat, 03 Sep 2016 22:01:49 -0700
void writeln(T...)(T args) { if (__ctfe){ debug { __ctfeWriteln(args); } } else { // ... current implementation } }
That will not work. The signature is void __ctfeWriteln(const string s)