On Tuesday, 6 September 2016 at 04:32:52 UTC, Daniel Kozak wrote:
Dne 6.9.2016 v 06:14 mogu via Digitalmars-d napsal(a):
On Tuesday, 6 September 2016 at 01:17:00 UTC, Timothee Cour
wrote:
is there a way to do this efficiently with associative arrays:
aa[key]=value;
auto ptr=key in aa;
without suffering the cost of the 2nd search (compiler should
know ptr during aa[key]=value but it's not exposed it seems)
auto pa = &(aa[key] = value);
Yep, but this is a implementation detail, so be careful
My question as well. Occurs often when I use AAs. The above
technique works in cases I've tried. However, to Daniel's point,
from the spec I don't find it clear if it's expected to work. It
would be useful to have better clarity on this. Anyone have more
details?
Below is a test for simple class and struct cases, they work at
present. The template is the type of helper I've wanted. I don't
trust this particular template, but it'd be useful to know if
there is a way to get something like this.
--Jon
/* Note: Not general template. Fails for nested classes (compile
error). */
T* getOrInsertNew(T, K)(ref T[K] aa, K key)
if (is(T == class) || is(T == struct))
{
T* p = (key in aa);
static if (is (T == class))
return (p !is null) ? p : &(aa[key] = new T());
else static if (is(T == struct))
return (p !is null) ? p : &(aa[key] = T());
else
static assert(0, "Invalid object type");
}
class FooClass { int x = 0; }
struct BarStruct { int x = 0; }
void main(string[] args)
{
FooClass[string] aaFoo;
BarStruct[string] aaBar;
/* Class is reference type. Pointer should be to instance in
AA. */
auto foo1 = aaFoo.getOrInsertNew("foo1");
foo1.x = 100;
auto foo1b = getOrInsertNew(aaFoo, "foo1");
assert(foo1 == foo1b && foo1.x == foo1b.x && foo1b.x == 100);
/* Struct is value type. Will pointer be to instance in AA? */
auto bar1 = aaBar.getOrInsertNew("bar1");
bar1.x = 100;
auto bar1b = getOrInsertNew(aaBar, "bar1");
assert(bar1 == bar1b && bar1.x == bar1b.x && bar1b.x == 100);
import std.stdio;
writeln("Success");
}