Re: Why doesn't std.variant.visit automatically call the provided delegates?

[Adam D. Ruppe via Digitalmars-d]

On Saturday, 5 November 2016 at 08:27:49 UTC, Nemanja Boric wrote:
    // This - does nothing
    variant.visit!(    (string s) => { enforce(false); x = 2; },

It calls the function... which returns a delegate, which you 
never called.

This is one of the most common mistakes people are making: {} in 
D is a delegate, and () => is a delegate, therefore () => {} is a 
delegate that returns a delegate... usually NOT what you want.

What you wrote is equivalent to writing

delegate() callback(string s) {
   return delegate() {
         enforce(false);
         x = 2;
   };
}


Do not use the => syntax if there is more than one expression. 
You'll get what you want by simply leaving the => out:


    // This works as expected
    variant.visit!(    (string s) { x = 2; },
                       (int i)    { x = 3; });