Re: Why do "const inout" and "const inout shared" exist?

[Walter Bright via Digitalmars-d]

On 7/1/2017 3:12 PM, Timon Gehr wrote:

const(const(T))     = const(T)
const(immutable(T)) = immutable(T)
const(inout(T))     = ?

It used to be the case that const(inout(T)) = const(T), but this is wrong, because if we replace 'inout' by 'immutable', the result should be immutable(T), not const(T). Hence const(inout(T)) cannot be reduced further.

If const(inout(T)) is reduced to inout(T), it works.