Re: Why do "const inout" and "const inout shared" exist?

[Andrei Alexandrescu via Digitalmars-d]

On 07/02/2017 09:49 AM, Andrei Alexandrescu wrote:
On 07/02/2017 09:48 AM, Andrei Alexandrescu wrote:
     *p = 42; // should be a shared write, it's not

I meant:

     p = new int; // should be a shared write, it's not

Dognabbit. No, I meant the previous one! The pointer itself is private 
to gun. -- Andrei