On Sunday, 28 January 2018 at 06:44:06 UTC, Shachar Shemesh wrote:
On 28/01/18 08:33, Mike Franklin wrote:
On Sunday, 28 January 2018 at 06:25:51 UTC, Shachar Shemesh
wrote:
What will the following code print? Do not use the compiler:
import std.stdio;
struct A {
int a = 1;
void initialize() {
a = a.init;
}
}
void main() {
A a;
a.initialize();
writeln(a.a);
}
I find this behavior unexpected.
Works exactly as I predicted.
Good for you.
I think the compiler should warn about such a case.
I also run the test and it worked as I expected. It seems pretty
straingtforward logic. I wonder if I didn't get your question
right. What result were you expecting and why?
