Phil Deets wrote:
On Fri, 04 Dec 2009 11:06:31 -0500, Don <[email protected]> wrote:


Here's a table of equivalences.

a!<>=b         (a!=a) || (b!=b)
a<>b           (a==a) && (b==b) && (a!=b)
a!<>b          (a!=a) || (b!=b) || (a!=b)
a<>=b          (a==a) && (b==b)
a!<=b          !(a<=b)
a!<b           !(a<b)
a!>=b          !(a>=b)
a!>b           !(a>b)
a!>=b          !(a>=b)

Obviously if a or b is known at compile time, or if it is known not to be NaN, many of the <> clauses can be dropped.


Isn't a!<>b equivalent to (a!=a) || (b!=b) || (a==b)?

Yes.

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