On 10/5/18 5:41 AM, Kagamin wrote:
On Thursday, 4 October 2018 at 12:51:27 UTC, Shachar Shemesh wrote:
More to the point, however, expanding the call to the second form
means that I can *never* supply non-default values to arg1 and arg2.
You wrote it yourself: f!()(true, 'S')
This is a terrible workaround. It looks OK with no vararg parameters,
but lousy if you have any.
i.e.:
f(arg1, arg2, arg3, true, 'S')
becomes:
f!(typeof(arg1), typeof(arg2), typeof(arg3))(arg1, arg2, arg3, true, 'S');
-Steve
