Walter Bright wrote:
Chris Nicholson-Sauls wrote:
Walter Bright wrote:
Andrei Alexandrescu wrote:
I asked in vain for is(var == ref), is(var == out) etc.
That's because 'is' works with types, not symbols. It didn't fit.
is(typeof(var) == ref) ?
No, because ref is not part of the type. It's a storage class.
Speaking of isLazy - any fresh ideas on dissing lazy? FWIW we can
replace it with the conversion of expressions to delegates. The
resulting situation is liable to a few ambiguities but is much better
than lazy.
Andrei
