On 06/02/2010 02:29 PM, Philippe Sigaud wrote:
On Wed, Jun 2, 2010 at 19:57, bearophile <[email protected] <mailto:[email protected]>> wrote: Philippe Sigaud: > What, do you also need the no-arg version of iota? > > :-p I'd like a generator (range) similar to the Python itertools.count, that yields numbers starting from the given number (defaulting to zero) and just goes on and on. You can use it in many situations: http://docs.python.org/library/itertools.html#itertools.count Yes, it's handy. It's one of the first range I made, a year ago.
iota(n, n.max) is close. Well, it's not infinite, but cycle(iota(n, n.max)) is. Probably a version using BigInt would be most sensible.
Andrei
