On 2010-08-27 12:53:07 -0400, Gabriel Huau <[email protected]> said:
void main()
{
Foo l = new Foo();
void delegate() dg;
dg = &l.test;
auto a = spawn(dg);
a.send("test");
}
I have tested and it worked.
But by passing the this pointer of your Foo object to another thread,
you've broken the rules about sharing memory between threads.
If Foo was a shared or synchronized type, then this could be made to
work safely (with some adaptation to make the compiler aware of what
delegates can be safely shared.)
--
Michel Fortin
[email protected]
http://michelf.com/
