Will uniform function call syntax apply to operator overloads?

[Peter Alexander]

In short, when UFC is working on all types, will this be possible:
Foo opBinary(string op)(Foo a, Foo b)
{
    return ...;
}

Foo x, y;
Foo z = x + y;

My reasoning here is that x + y is supposedly sugar for 
x.opBinary!("+")(y), so the free opBinary defined above could be chosen 
as a pseudo member of Foo.

Will this be possible?