On Sun, 2011-03-06 at 10:08 -0500, bearophile wrote:
> Russel Winder:
>
> > reduce ! ( ( a , b ) { return a + b ; } ) ( 0.0 , outputData )
> >
> > works just fine, but:
> >
> > reduce ! ( function double ( double a , double b ) { return a + b ;
> > } ) ( 0.0 , outputData )
>
>
> import std.stdio, std.algorithm, std.range;
>
> void main() {
> auto outputData = iota(1.0, 10.0);
>
> auto r1 = reduce!((a, b){ return a + b; })(0.0, outputData);
> writeln(r1);
>
> auto r2 = reduce!((double a, double b){ return a + b; })(0.0, outputData);
> writeln(r2);
>
> auto r3 = reduce!("a + b")(0.0, outputData);
> writeln(r3);
>
> auto r4 = reduce!q{a + b}(0.0, outputData);
> writeln(r4);
>
> auto r5 = reduce!q{a + b}(outputData); // not exactly the same
> writeln(r5);
> }
>
> Bye,
> bearophile
So why does:
reduce ! ( function double ( double a , double b ) { return a + b ; } )
( 0.0 , outputData )
fail? It implies that a function literal and a lambda are significantly
different things as far as the compiler is concerned.
--
Russel.
=============================================================================
Dr Russel Winder t: +44 20 7585 2200 voip: sip:[email protected]
41 Buckmaster Road m: +44 7770 465 077 xmpp: [email protected]
London SW11 1EN, UK w: www.russel.org.uk skype: russel_winder
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