Morlan:
> I did not ask what to do to compile it. I knew that 54L would do. The problem
> is
> that in the example I explicitely specify the template parameter as long* so
> there
> is no reason for the compiler to try and guess T from the type of the function
> argument. There is something wrong here.
The compiler is not guessing the type here. It's just that the type the
template is explicitly instantiated with, and the type T of the data, aren't
the same. You see it better with this simpler example:
import std.stdio;
void foo(T)(T x) if(is(T == int)) {
writeln("1");
}
void foo(T)(T x) if(!is(T == int)) {
writeln("2");
}
void main() {
foo(1); // 1
foo(1L); // 2
foo!(int)(1); // 1
foo!(long)(1L); // 2
foo!(long)(1); // error
foo!(int)(1L); // error
}
Bye,
bearophile
