On 29.04.2011 18:13, Steven Schveighoffer wrote:
> Static opCall is possible, but I wasn't aware of the other operator overloads
> being possible.
I wasn't too - it is not mentioned anywhere, just tried it.
> Note that opAssign is a valid symbol name, so it can be used in places even
> where it doesn't overload assignment, such as a static or global function.
> It just won't map to any operator usage.
Well, the fact is - it maps. If I've static opAssign() defined, it is called
when I assign something to an object.
Even more fun - static opAdd() maps too, and - wow! - if it returns new
object, i.e. construction like:
X x;
x = x + 3;
then it will allocate new instance of X, where: static typeof(this) opAdd(int
i) { return new X(i); }
I am impressed... :)
/Alexander
