On 9/26/2011 9:36 AM, bearophile wrote:
In similar situations I suggest you to minimize your code, so both you
ans us are able to better see the situation and the problem. Doing
that you often don't need help. Bye, bearophile
Hope this is better:
void main() {
(Test() + Test()).get(0.0);
}
struct Sum(T1, T2) {
T1 a;
T2 b;
auto ref get(T2...)(T2 args) {
return (a + b).get(args); // Why is calling get() considered a
"forward reference"?
}
}
struct Test {
auto ref get(T2...)(T2 value) { return 0; }
Sum!(typeof(this), T2) opAdd(T2)(T2 other) const {
return typeof(return)(this, other);
}
}
