On Thu, 27 Oct 2011 12:58:57 -0400, Steve Teale
<[email protected]> wrote:
On Thu, 27 Oct 2011 16:16:26 +0200, Alex Rønne Petersen wrote:
On 27-10-2011 15:50, Steve Teale wrote:
Surely Variant.init should do the trick?
Dmitry,
Are you talking about the new std.variant - I don't see 'init'
currently.
Steve
He is probably referring to the 'init' property on the *type*, i.e.
int.init and so on.
- Alex
Same catch 22. In order to have an init property, the Variant would have
to have been set to some type, at which point hasValue() would say yes.
Steve
import std.variant;
void main()
{
Variant v = 1;
assert(v.hasValue());
v = v.init;
assert(!v.hasValue());
}
-Steve
