On Dec 1, 2011, at 7:28 AM, Timon Gehr wrote: > On 12/01/2011 02:06 AM, Sean Kelly wrote: >> >> >> This seems wrong to me. If a function is callable in a shared scenario, why >> would it not be callable in an unshared scenario? At worst depending on how >> shared were implemented the call would be slower than an unshared version >> but still entirely correct. > > Because of escaping.
I'd overlooked that. Thanks.
