On 2/13/12 7:46 AM, David Nadlinger wrote:
On 2/13/12 2:43 PM, Andrej Mitrovic wrote:auto u = (a, b) => cast(ubyte)uniform(a, b);Which would make 'u' a template. I'm not sure what the exact syntax was that was requested though.This could never work without major changes to the language, because 'u' cannot be assigned a type. David
alias (a, b) => cast(ubyte)uniform(a, b) u;should work. This makes is a case where the discussed syntax "alias defined = definee;" would be helpful.
Andrei
