On 14-03-2012 19:00, H. S. Teoh wrote:
Code:
        import std.stdio;
        version(explicit) {
                void func(dstring s) {
                        dstring t = s;
                        writeln(t);
                }
        } else {
                void func(S)(S s) {
                        dstring t = s;  // line 10
                        writeln(t);
                }
        }
        void main() {
                func("abc");
        }

If version=explicit is set, the program compiles fine. But if not, then
the compiler complains:

        test.d:10: Error: cannot implicitly convert expression (s) of type 
string to immutable(dchar)[]

What do I need to do to make the template version of func trigger
implicit conversion of the string lit to dstring? What I'm trying to do
is to templatize dstring as well, but still benefit from the
string->dstring conversion when instantiated with dstring.

(Ditto with implicit conversion to wstring.)


T


I doubt that such an implicit conversion even exists. You have to prefix the string appropriately, e.g.:

string s = "foo";
wstring w = w"bar";
dstring d = d"baz";

--
- Alex

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