Thanks. This is very helpful.
Going back to my original example, if
x = nd.ones(shape=(10,), ctx=gpu(0))
y = 2.0
Then the operation of
`result = x*y`
involves the following operations:
op1. copy y from main memory to GPU
op2. broadcast if needed
op3. multiplication
and all the operations are non-blocking. Does this sound right?
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