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Yes, it will.
The GNU Radio scheduler calls your block's work() function whenever it
needs new data.

Anyway, this is a very basic principle of GR; I recommend working
through the "creating an OOT module" tutorial, it's really great!

Greetings,
Marcus

On 02.02.2014 14:14, MHMND Herath wrote:
> Dear Sir I created a C++ sync block and inserted
> 
> out[i]=in[i-100] I wanted to get 100th earliest sample
> continuously. It worked. But I wanted to know will this correct
> when it connected to a source continuously. Thanks Neil
> 
> 
> 
> 
> _______________________________________________ Discuss-gnuradio
> mailing list [email protected] 
> https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
> 
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