Hi Ali, I see an imaginary part whenever the real part drops from 1 to 0; which is to be expected, since the Hilbert filter is a high pass one.
Background: Remember, this is the digital world. There is no Hilbert transform here -- there could only be a discrete Hilbert transform. And even that is a convolution with an infinite series and cannot be done. So the Hilbert transform is a FIR approximation. Greetings, Marcus On 17.08.2014 17:04, jason sam wrote: > Hi, > I have made a simple flowgraph as attached.I have on query that when i > observe the signal coming out of the 'Hilbert transform' block using a > time sink then its imaginary part is shown to be zero.According to the > theory the hilbert transform of a signal x(t) is: > x(t)+jx~(t) > where x~(t) is the quadrature phase component of x(t).Then why is the > signal from the hilbert block has zero imaginary part?? > Regards, > Ali > > > _______________________________________________ > Discuss-gnuradio mailing list > [email protected] > https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
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