Hi,
If you want the channel impulse response you may simply perform an IFFT on
the channel frequency response estimated by the equalizer of gr-dtv/dvbt
(don't forget to "shift" it, so that it starts at 0 and ends at 2\pi). I
think this is performed by the block "Demod Reference Signals", but it does
not output the estimated channel. However, modifications should be
relatively simple once you dig a little bit into the code and understand
what you are looking for. You may look at the corresponding blocks at
gr-isdbt ("Sync and Channel Estimation") to look for ideas on how to
achieve this.
best
Federico

2016-10-02 20:03 GMT-03:00 Tom Rondeau <[email protected]>:

> On Sun, Oct 2, 2016 at 2:40 PM, Cinaed Simson <[email protected]>
> wrote:
>
>> On 10/01/2016 04:46 PM, Juan Antonio wrote:
>> > Hello, someone would know how to calculate the impulse response of a
>> > COFDM, DVB-T channel with an SDR device?
>> >
>> > Thank you in advance
>> >
>> >
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>> >
>>
>> An inverse DFT on a sinc function in the frequency domain yields a sine
>> function in the time domain. And a DFT on the sine function in the time
>> domain yields a sinc function in the frequency domain.
>>
>
>
> No, the DFT of a sine function is an impulse. More formally, a Dirac delta
> function.
>
> The sinc function is the result of a truncated sine wave where the sine
> wave is multiplied by a square wave. The DFT of a square wave is a sinc, so
> with a truncated sine wave in the time domain, you are convolving a sinc
> with a delta function in the frequency domain.
>
> Tom
>
>
>
>> I presume the "C" in COFDM means to chop up the bandwidth into carriers
>> such that the sinc function in one channel hits nulls in the other
>> channels.
>>
>> Piece of cake in theory.
>>
>> There's a gr-dvbt project on github
>>
>>   https://github.com/BogdanDIA/gr-dvbt
>>
>> I don't know anything about it - I don't even know if it works.
>>
>> -- Cinaed
>>
>
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